Question 2

Both x and y vary inversely with each other. When x is 10, y is 6, which of the following is not a possible pair of corresponding values of x and y?
(a) 12 and 5
(b) 15 and 4
(c) 25 and 2.4
(d) 45 and 1.3

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Solution

Since, x and y vary inversely, i.e. $x \times y = k$ (constant)
If x =10 and y =6
$∴ x y = 10 \times 6 = 60$
In option (a), $12 \times 5 = 60$
In option (b), $15 \times 4 = 60$
In option (c), $24 \times 2.4 = 60$
But in option (d), $45 \times 1.3 = 58.3$
Hence, option (d)is correct.

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Similar questions

Question 2

Both x and y vary inversely with each other. When x is 10, y is 6, which of the following is not a possible pair of corresponding values of x and y?
(a) 12 and 5
(b) 15 and 4
(c) 25 and 2.4
(d) 45 and 1.3

Q. Both x and y vary inversely with each other. When x is 10, y is 6, which of the following is not a possible pair of corresponding values of x and y?
(a) 12 and 5
(b) 15 and 4
(c) 25 and 2.4
(d) 45 and 1.3

Question 16

Both x and y vary directly with each other and when x is 10, y is 14, which of the following is not a possible pair of corresponding values of x and y?
(a) 25 amd 35
(b) 35 and 25
(c) 35 and 49
(d) 15 and 21

Q. If

x

and

y

vary inversely to each other. When

x = 10, y = 6

. Which is not a possible pair of corresponding values of

x

and

y

Question 1

Both u and v vary directly with each other. When u is 10, v is 15, which of the following is not a possible pair of corresponding values of u and v?
(a) 2 and 3
(b) 8 and 12
(c) 15 and 20
(d) 25 and 37.5

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Direct Proportions

Standard VII Mathematics

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Question 2 Both x and y vary inversely with each other. When x is 10, y is 6, which of the following is not a possible pair of corresponding values of x and y? (a) 12 and 5 (b) 15 and 4 (c) 25 and 2.4 (d) 45 and 1.3

Since, x and y vary inversely, i.e. x×y=k (constant) If x =10 and y =6 ∴xy=10×6=60 In option (a),12×5=60 In option (b),15×4=60 In option (c),24×2.4=60 But in option (d), 45×1.3=58.3 Hence, option (d)is correct.

Question 2

Both x and y vary inversely with each other. When x is 10, y is 6, which of the following is not a possible pair of corresponding values of x and y?
(a) 12 and 5
(b) 15 and 4
(c) 25 and 2.4
(d) 45 and 1.3

Since, x and y vary inversely, i.e. $x \times y = k$ (constant)
If x =10 and y =6
$∴ x y = 10 \times 6 = 60$
In option (a), $12 \times 5 = 60$
In option (b), $15 \times 4 = 60$
In option (c), $24 \times 2.4 = 60$
But in option (d), $45 \times 1.3 = 58.3$
Hence, option (d)is correct.