Question

Question 2
Compute the heat generated while transferring 96000 coulombs of charge in one hour through a potential difference of 50 V.

Answer 1

Given Charge, Q = 96000 C
Time, $t=1hr=60\times 60=3600s$
Potential difference, V= 50 volts
Now, we know that heat generated, H = VIt
So, we have to calculate $I$ first.
As, $I=\frac{Q}{t}$
$\therefore I=\frac{96000}{3600}=\frac{80}{3}A$
$H=50\times \frac{80}{3}\times 60\times 60=4.8\times {10}^{6}J$
Therefore, the heat generated is $4.8\times {10}^{6}J$.