Question 2
Draw an angle of measure 147∘ and construct its bisector.
Steps of construction:
(a) Draw a ray OA.
(b) With the help of protractor, construct ∠AOB=147∘
(c) Taking centre O and any convenient radius, draw an arc which intersects the arms ¯¯¯¯¯¯¯¯OA and ¯¯¯¯¯¯¯¯OB at P and Q respectively.
(d) Taking P as centre and radius more than half of PQ, draw an arc.
(e) Taking Q as centre and with the same radius, draw another arc which intersects the previous at R.
(f) Join OR and produce it.
(g) Thus, ¯¯¯¯¯¯¯¯OR is the required bisector of ∠AOB