Question

Question 2
Find the area of a quadrant of a circle whose circumference is 22 cm.

Answer 1

Quadrant of a circle means sector is making angle ${90}^{\circ }$
Circumference of the circle $=2\pi r=22cm$
Radius of the circle $=r=\frac{22}{2\pi }cm=\frac{7}{2}cm$
Area of the sector making angle ${90}^{\circ }=\left(\frac{{90}^{\circ }}{{360}^{\circ }}\right)\times \pi r^{2}c{m}^2$
$=\left(\frac{1}{4}\right)\times (\frac{7}{2}{)}^2\pi =(\frac{49}{16})\pi c{m}^2=(\frac{49}{16})\times (\frac{22}{7})c{m}^2=\frac{77}{8}c{m}^2$