Question 2 iSimplify 3-32-2 -

Name: NCERT - Grade 09 - Mathematics - Number Systems - Q20_1
Uploaded: 2022-07-04T10:36:42+05:30
Description: (3+√(3))(2+√(2)) =3 × 2+3×√(2)+ √(3)× 2 + √(3)×√(2) = 6+ 3√(2)+2 nbsp;√(3)+√(6) ...

(3+√(3))(2+√(2)) =3 × 2+3×√(2)+ √(3)× 2 + √(3)×√(2) = 6+ 3√(2)+2 nbsp;√(3)+√(6) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Monomial and Binomial Surds

Question 2 iS...

Question

Question 2 (i)
Simplify $(3 + \sqrt{3}) (2 + \sqrt{2})$ .

Open in App

Solution

$(3 + \sqrt{3}) (2 + \sqrt{2})$
$= 3 \times 2 + 3 \times \sqrt{2} + \sqrt{3} \times 2 + \sqrt{3} \times \sqrt{2} = 6 + 3 \sqrt{2} + 2 \sqrt{3} + \sqrt{6}$

Suggest Corrections

Similar questions

Question 3 (i)
Simplify:

$2^{\frac{2}{3}} {.2}^{\frac{1}{5}}$

Question 2 (i)
Simplify $(3 + \sqrt{3}) (2 + \sqrt{2})$ .

Question 180(vi)

Simplify :
$\frac{(3^{- 2})^{2} \times (5^{2})^{- 3} \times (t^{- 3})^{2}}{(3^{- 2})^{5} \times (5^{3})^{(- 2)} \times (t^{- 4})^{3}}$

Question 180(vi)

Simplify :
$\frac{(3^{- 2})^{2} \times (5^{2})^{- 3} \times (t^{- 3})^{2}}{(3^{- 2})^{5} \times (5^{3})^{(- 2)} \times (t^{- 4})^{3}}$

Question 2 (ii)
Find : $32^{\frac{2}{5}}$

Join BYJU'S Learning Program

Explore more

Monomial and Binomial Surds

Standard IX Mathematics

Join BYJU'S Learning Program

Question 2 (i) Simplify (3+√3)(2+√2) .

(3+√3)(2+√2) =3×2+3×√2+√3×2+√3×√2=6+3√2+2√3+√6

Question 2 (i)
Simplify $(3 + \sqrt{3}) (2 + \sqrt{2})$ .

$(3 + \sqrt{3}) (2 + \sqrt{2})$
$= 3 \times 2 + 3 \times \sqrt{2} + \sqrt{3} \times 2 + \sqrt{3} \times \sqrt{2} = 6 + 3 \sqrt{2} + 2 \sqrt{3} + \sqrt{6}$