Question

Question 2(ii)
Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube:
256

Answer 1

256
Prime factors of $256=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2$
Here one factor 2 is required to make a 3’s group.
Therefore, 256 must be multiplied by 2 to make it a perfect cube.
$\begin{array}{cc}2& 256\\ 2& 128\\ 2& 64\\ 2& 32\\ 2& 16\\ 2& 8\\ 2& 4\\ 2& 2\end{array}$