Question 2 (iii)
Choose the correct option and justify your choice.
(iii) sin2A = 2sinA is true when A =
(A) 0∘
(B) 30∘
(C) 45∘
(D) 60∘
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Solution
Option (A) is correct.
sin 2A = 2 sin A is true when A = 0∘
As sin 2A = sin 0∘ = 0
2 sin A = 2sin 0∘ = 2×0 = 0 Another Method
sin 2A = 2sin A cos A ⇒2sin A cos A =2 sin A ⇒ cos A = 1 ⇒ A = 0∘