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Factorization of a Quadratic Trinomial

Question 2iii...

Question

Question 2(iii)
Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the following products:
$(4 x - 5) (4 x - 1)$

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Solution

$(4 x - 5) (4 x - 1) = (4 x)^{2} + (- 5 - 1) 4 x + (- 5) \times (- 1)$
$= 16 x^{2} + (- 6) \times 4 x + 5$ $[U s i n g i d e n t i y (x + a) (x + b) = x^{2} + (a + b) x + a b]$ $= 16 x^{2} - 24 x + 5$

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