Question

Question 2
In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.

Answer 1

The point which is equidistant from all the sides of a triangle is incenter of triangle. Incentre of triangle is the intersection point of angle bisectors of interior angles of that triangle.

Here in $\Delta$ABC we can find the incentre of this triangle by drawing the angle bisectors of interior angles of this triangle. I is the point where these angle bisectors are intersecting each other. So, I is the point, equidistant from all the sides of $\Delta$ABC.