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Question

Question 2
In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that POQ=110, then PTQ is equal to
(A) 60
(B) 70
(C) 80
(D) 90

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Solution

OP and OQ are radii of the circle to the tangents TP and TQ respectively.
Since, t
he line drawn from the centre of the circle to the tangent is perpendicular to the tangent.
OP TP and OQ TQ.
OPT=OQT=90
In quadrilateral POQT,
Sum of all interior angles = 360
PTQ+OPT+POQ+OQT=360PTQ+90+110+90=360PTQ=70
PTQ is equal to option (B) 70.

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