Question 2
In the following figure, D and E are two points on BC such that BD = DE= EC. Show
that area (ABD) = area (ADE) = area (AEC).
![](https://infinitestudent-migration-images.s3-us-west-2.amazonaws.com/_d53a8ae9617633d93860974703429d2fc4a4d20f20160920-14301-zyq6jz.png)
[Remark: Note that by taking BD=DE=EC, the triangle ABC is divided into three Triangles ABD, ADE and AEC of equal areas. In the same way, by dividing BC into n Equal parts and joining the points of the division so obtained to the opposite vertex of BC, you can divide
ΔABC into triangles of equal areas.]