Question 2(iv)
Divide the given polynomial by the given monomial
$(x^{3} + 2 x^{2} + 3 x) \div 2 x$

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Solution

$x^{3} + 2 x^{2} + 3 x = x (x^{2} + 2 x + 3) (x^{3} + 2 x^{2} + 3 x) \div 2 x = \frac{x (x^{2} + 2 x + 3)}{2 x} = \frac{1}{2} (x^{2} + 2 x + 3)$

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Q. Divide the given polynomial by the given monomial

(x^{3} + 2 x^{2} + 3 x) \div 2 x

Q. Question 2(iv)
Divide the given polynomial by the given monomial

(x^{3} + 2 x^{2} + 3 x) \div 2 x

Q. Question 2(i)
Divide the given polynomial by the given monomial

(5 x^{2} - 6 x) \div 3 x

Divide the given polynomial by the given monomial.

$(i) (5 x^{2} - 6 x) \div 3 x$

$(i i) (3 y^{8} - 4 y^{6} + 5 y^{4}) \div y^{4}$

$(i i i) 8 (x^{3} y^{2} z^{2} + x^{2} y^{3} z^{2} + x^{2} y^{2} z^{3}) \div 4 x^{2} y^{2} z^{2}$

$(i v) (x^{3} + 2 x^{2} + 3 x) \div 2 x$ . [4 MARKS]

Divide the given polynomial by the given monomial:
$(2 y^{3} + 3 y^{2} + 12 y) \div 3 y$

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Division of a Polynomial by a Monomial

Standard VI Mathematics

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Question 2(iv) Divide the given polynomial by the given monomial (x3+2x2+3x)÷2x

x3+2x2+3x=x(x2+2x+3)(x3+2x2+3x)÷2x=x(x2+2x+3)2x=12(x2+2x+3)

Question 2(iv)
Divide the given polynomial by the given monomial
$(x^{3} + 2 x^{2} + 3 x) \div 2 x$

$x^{3} + 2 x^{2} + 3 x = x (x^{2} + 2 x + 3) (x^{3} + 2 x^{2} + 3 x) \div 2 x = \frac{x (x^{2} + 2 x + 3)}{2 x} = \frac{1}{2} (x^{2} + 2 x + 3)$