Question 2 (iv)
Write first four terms of the A.P. when the first term "a" and the common difference "d" are given as follows.
(iv) $a = - 1, d = \frac{1}{2}$

Open in App

Solution

$G i v e n, a = - 1 a n d d = \frac{1}{2}$
Let the group of numbers be $a_{1}, a_{2}, a_{3}, a_{4}, a_{5}, \dots$
$a_{1} = a = - 1 a_{2} = a_{1} + d = - 1 + \frac{1}{2} = - \frac{1}{2} a_{3} = a_{2} + d = - \frac{1}{2} + \frac{1}{2} = 0 a_{4} = a_{3} + d = 0 + \frac{1}{2} = \frac{1}{2}$

Clearly, the series will be :
$- 1, - \frac{1}{2}, 0, \frac{1}{2}$

Hence, the first four terms of this A.P. are :
$- 1, - \frac{1}{2}, 0 a n d \frac{1}{2}$

Suggest Corrections

Similar questions

Q. Question - 2 (iv)
Write first four terms of the A.P. when the first term "a" and the common difference "d" are given as follows.
(iv)

a = - 1, d = \frac{1}{2}

Question 2 (ii)
Write first four terms of the A.P. when the first term "a" and the common difference "d" are given as follows.
(ii) a = -2, d = 0

Question 2 (v)
Write first four terms of the A.P. when the first term "a" and the common difference "d" are given as follows.
(v) $a = - 1.25, d = - 0.25$

Join BYJU'S Learning Program

Explore more

Common Difference

Standard IX Mathematics

Join BYJU'S Learning Program

Question 2 (iv) Write first four terms of the A.P. when the first term "a" and the common difference "d" are given as follows. (iv) a=−1, d=12

Given,a=−1 and d=12 Let the group of numbers be a1,a2,a3,a4,a5, … a1=a=−1a2=a1+d=−1+12=−12a3=a2+d=−12+12=0a4=a3+d=0+12=12 Clearly, the series will be : −1,−12,0,12 Hence, the first four terms of this A.P. are : −1,−12,0 and 12

Question 2 (iv)
Write first four terms of the A.P. when the first term "a" and the common difference "d" are given as follows.
(iv) $a = - 1, d = \frac{1}{2}$