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Question 2
Theinner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm.The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g.
[Assume π=227]


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Solution

Inner radius,
(r1) of the cylindrical pipe =(242)cm=12 cm

Outer radius,
(r2) of the cylindrical pipe =(282)cm=14 cm

Height (h) of the pipe = length of the pipe = 35 cm

Volume of the pipe
=π(r22r21)h cm3=110×52 cm3=5720 cm3

Mass of 1 cm3 wood=0.6 g

Mass of 5720 cm3 wood=(5720×0.6) g=3432 g

= 3.432 kg (1000 g = 1 kg)


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