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Question

Question 2(vii)
Factorise the following expressions
10a215b2+20c2

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Solution

10a2=2×5×a×a15b2=3×5×b×b20c2=2×2×5×c×cThe common factor is 510a215b2+20c2=(2×5×a×a)(3×5×b×b)+(2×2×5×c×c)=5[(2×a×a)(3×b×b)+(2×2×c×c)]=5(2a23b2+4c2)

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