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(a + b)^2 = a^2 + 2ab +b^2

Question 2vii...

Question

Question 2(vii)
Factorise
$(x^{2} - 2 x y + y^{2}) - z^{2}$

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Solution

$(x^{2} - 2 x y + y^{2}) - z^{2} = (x - y)^{2} - (z)^{2} [(a - b)^{2} = a^{2} - 2 a b + b^{2}] = (x - y - z) (x - y + z) [a^{2} - b^{2} = (a - b) (a + b)]$

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Factorise
$(x^{2} - 2 x y + y^{2}) - z^{2}$

\frac{x^{2} + y^{2} - z^{2} + 2 x y}{x^{2} - y^{2} - z^{2} - 2 y z} .

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(a + b)^2 = a^2 + 2ab +b^2

Standard VII Mathematics

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