False
In the figure, AB and AC are two chords of a circle.
Join OB and OC.
In ΔOAB and ΔOAC
OA = OA [common sides]
OB = OC [both are the radius of circle]
Here, we are not able to show that either any angle or the third side is equal.
Hence ΔOAB is not congruent to ΔOAC
∠OAB≠∠OAC