Question

Question 20
If an electric iron of 1200 W is used for 30 minutes every day, find electric energy consumed in the month of April.

Answer 1

$Power,P=\frac{1200}{1000}=1.2kW$
$Time,t=\frac{30}{60}=0.5h$
$E=Power\times time\times days$
$E=1.2\times .5\times 30$
$E=18kWh$