Question

Question 21
The reciprocal of $\frac{-3}{8}\times \left(\frac{-7}{13}\right)$ is
(a) $\frac{104}{21}$
(b) $\frac{-104}{21}$
(c) $\frac{21}{104}$
(d) $\frac{-21}{104}$

Answer 1

Given number is $\frac{-3}{8}\times \left(\frac{-7}{13}\right)$
The product of $\frac{-3}{8}\times \left(\frac{-7}{13}\right)=\frac{21}{104}$
Hence, the multiplication inverse of $\frac{21}{104}$ is $\frac{104}{21}$ i.e option (a).