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Standard VII

Mathematics

Chance and Probability

Question 22 i...

Question

Question 22 (ii)
(ii) A student argues that there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9,10, 11 and 12. Therefore each of them has a probability $\frac{1}{11}$ . Do you agree with this argument? Justify your answer.

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Solution

(ii) I do not agree with the argument given here. Justification has already been given in part (i).

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Similar questions

A student argues that there are

11

possible outcomes (sum of numbers on both dice)

2, 3, 4, 5, 6, 7, 8, 9, 10, 11

and

12

when we throws two dice simultaneously. Therefore each of them has a probability

\frac{1}{11} .

Do you agree with this argument? Justify your answer.

Q. (i) Complete the following table:

Event: 'Sum on $2$ dice'	$2$	$3$	$4$	$5$	$6$	$7$	$8$	$9$	$10$	$11$	$12$
Probability	$\frac{1}{36}$						$\frac{5}{36}$				$\frac{1}{36}$

(ii) A student argues that there are

11

possible outcomes

2, 3, 4, 5, 6, 7, 8, 9, 10, 11

and

12

. Therefore, each of them has a probability

\frac{1}{11}

. Do you agree with this argument?
Justify your answer.

(i) Complete the following table:

$\begin{matrix} Event:'Sum of 2 dice' & Probability 2 & \frac{1}{36} 34567 8 & \frac{5}{36} 91011 12 & \frac{1}{36} \end{matrix}$

(ii) A student argues that there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability $\frac{1}{11}$ . Do you agree with this argument? Justify your answer.

Q. Two dice, one blue and one grey are thrown at the same time. Complete the following table:

Event: Sum on two dice'	2	3	4	5	6	7	8	9	10	11	12
Probability

From the above table a student argues that there are

11

possible outcomes

2, 3, 4, 5, 6, 7, 8, 9, 10, 11

and

12

. Therefore, each of them has a probability of

\frac{1}{11}

. Do you agree with this argument?

Two dice, one blue and one grey, are thrown at the same time.

(i) Write down all the possible outcomes and complete the following table:

Event:

Sum of two dice

Probability

(ii) A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability. Do you agree with this argument?

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Chance and Probability

Standard VII Mathematics

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Question 22 (ii) (ii) A student argues that there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9,10, 11 and 12. Therefore each of them has a probability 111. Do you agree with this argument? Justify your answer.

(ii) I do not agree with the argument given here. Justification has already been given in part (i).

Question 22 (ii)
(ii) A student argues that there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9,10, 11 and 12. Therefore each of them has a probability $\frac{1}{11}$ . Do you agree with this argument? Justify your answer.