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Exponent Numbers with Different Base and Same Power

Question 22In...

Question

Question 22

In the following question, out of the four options, only one is correct. Write the correct answer:

For a non-zero integer x, $(x^{4})^{- 3}$ is equal to:
(a) $x^{12}$
(b) $x^{- 12}$
(c) $x^{64}$
(d) $x^{- 64}$

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Solution

Using law of exponents, $(a^{m})^{n} = (a)^{m \times n} = (a)^{m n}$
Similarly , $(x^{4})^{- 3} = (x)^{4 \times (- 3)} = (x)^{- 12}$

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Exponent Numbers with Different Base and Same Power

Standard VII Mathematics

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