Question

Question 24
One ticket is drawn at random from a bag containing tickets numberd 1 to 40. The probability that the selected ticket has a number which is a multiple of 5 is
(a) $\frac{1}{5}$
(b) $\frac{3}{5}$
(c) $\frac{4}{5}$
(d) $\frac{1}{3}$

Answer 1

Number of total outcomes =40
Multiples of 5 between 1 to 40=5, 10,15,20,25,30,35,40
$\therefore$ Total number of possible outcomes =8
$\therefore$ Required probability =$\frac{8}{40}=\frac{1}{5}$