Question

Question 25(i)
A coin is tossed 3 times. List the possible outcomes. Find the probability of getting all heads?

Answer 1

The possible outcomes if a coin is tossed 3 times is
S = {(HHH), (TTT), (HTT), (THT), (TTH), (THH), (HTH), (HHT)}
$\therefore n\left(S\right)=8$
Let $E_1=$ Event of getting all heads = {(HHH)}
$\therefore n\left(E_1\right)=1$
$\therefore P\left(E_1\right)=\frac{n\left(E_1\right)}{n\left(S\right)}=\frac{1}{8}$