Question

Question 25(ii)
A coin is tossed 3 times. List the possible outcomes. Find the probability of getting at least 2 heads?

Answer 1

The possible outcomes if a coin is tossed 3 times is
S = {(HHH), (TTT), (HTT), (THT), (TTH), (THH), (HTH), (HHT)}
$\therefore n\left(S\right)=8$
Let $E_2$= Event of getting atleast 2 heads = {(HHT), (HTH), (THH), (HHH)}
$\therefore n\left(E_2\right)=4$
$\therefore P\left(E_2\right)=\frac{n\left(E_2\right)}{n\left(S\right)}=\frac{4}{8}=\frac{1}{2}$