Question

Question 25
Someone is asked to take a number from 1 to 100. The probability that it is a prime, is
(a) $\frac{1}{5}$
(b) $\frac{6}{25}$
(c) $\frac{1}{4}$
(d) $\frac{13}{50}$

Answer 1

Total numbers of outcomes =100
So, the prime numbers between 1 to 100 are 2,3,5,7.11,13,17,19,23,29,31,37,41, 43,47,53,56,61,67,71,73,79,83,89, abd 97.
$\therefore$ Total number of possible outcomes =25
$\therefore$ Required probability =$\frac{25}{100}=\frac{1}{4}$