Question 25
Two cubes have volumes in the ratio 1 : 64. The ratio of the area of a face of first cube to that of the other is
a) 1 : 4
b) 1 : 8
c) 1 : 16
d) 1 : 32
Let a and b be the edges of the two cubes respectively.
Then, according to the question,
a3:b3=1:64 [∵ volume of cube =(edge)3]
⇒a3b3=164
⇒(ab)3=(14)3⇒ab=14 [taking cube roots on both sides]
Now, ratio of areas, (ab)2=(14)2 [∵ surface area of cube =6×(edge)2]
⇒a2b2=116
∴a2:b2=1:16