Question

Question 27(ii)
A bag contains 10 red, 5 blue and 7 green balls. A ball is drawn at random. Find the probability of this ball being a green ball?

Answer 1

If a ball is drawn out of 22 balls (5 blue + 7 green + 10 red), then the total number of outcomes are
Let $E_2$= Event of getting a green ball
$n(E{)}_2=7$
$\therefore$ Required probability $=\frac{n\left(E_2\right)}{n\left(S\right)}=\frac{7}{22}$