Question 28 (iii)
$B_{1}, B_{2}$ and $B_{3}$ are three identical bulbs connected as shown in Figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(iii) How much power is dissipated in the circuit when all the three bulbs glow together?

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Solution

(iii) When all the three bulbs are connected,
Power dissipated, P=VI
The value of V= 4.5 V since all the bulbs are connected in parallel.
Therefore, $P = V I = 4.5 \times 3 = 13.5 W$

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Question 28 (i)
$B_{1}, B_{2}$ and $B_{3}$ are three identical bulbs connected as shown in figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(i) What happens to the glow of the other two bulbs when the bulb $B_{1}$ gets fused?

B_{1}, B_{2}

and

B_{3}

are three identical bulbs connected as shown in Figure 12.8. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
What happens to the glow of the other two bulbs when the bulbs

B_{1}

gets fused?

Question 28 (ii)
$B_{1}, B_{2}, a n d B_{3}$ are three identical bulbs connected as shown in figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(ii) What happens to the reading of $A_{1}, A_{2} A_{3}$ and A when the bulb $B_{2}$ gets fused?

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Question 28 (iii) B1, B2 and B3 are three identical bulbs connected as shown in Figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A. (iii) How much power is dissipated in the circuit when all the three bulbs glow together?

(iii) When all the three bulbs are connected, Power dissipated, P=VI The value of V= 4.5 V since all the bulbs are connected in parallel. Therefore, P=VI=4.5×3 =13.5 W

Question 28 (iii)
$B_{1}, B_{2}$ and $B_{3}$ are three identical bulbs connected as shown in Figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(iii) How much power is dissipated in the circuit when all the three bulbs glow together?

(iii) When all the three bulbs are connected,
Power dissipated, P=VI
The value of V= 4.5 V since all the bulbs are connected in parallel.
Therefore, $P = V I = 4.5 \times 3 = 13.5 W$