Question 3
For the AP –3, –7, –11,… can we find directly a30−a20 without actually finding a30anda20? Give the reason for your answer.
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Solution
True.
nth term of an AP, an=a+(n−1)d ∴a30=a+(30−1)d=a+29d anda20=a+(20−1)d=a+19d Now,a30−a20=(a+29d)−(a+19d)=10d
Common difference, d = -7 - (-3) = -7 + 3
= - 4 ∴a30−a20=10(−4)=−40