Question 3 (i)
Are the following pair of linear equations consistent ? justify your answer
- 3x - 4y = 12 and 4y + 3x = 12

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Solution

- 3x - 4y = 12 and 4y + 3x = 12
Here, $\frac{a_{1}}{a_{2}} = \frac{- 3}{3} = - 1, \frac{b_{1}}{b_{2}} = \frac{- 4}{4} = - 1$ and $\frac{c_{1}}{c_{2}} = \frac{12}{12} = 1$
$∴ \frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$
So, the given pair of linear equations is inconsistent and has no solution.

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Similar questions

- 3 x - 4 y = 12

4 y + 3 x = 12

Question 3 (iii)
Are the following pair of linear equations consistent? Justify your answer
2a + by = a and 4a + 2by -2a = 0; a, b $\neq$ 0

Question 1 (i)
Do the following pair of linear equations have no solution? Justify your answer.
2x + 4y = 3 and 12y + 6x = 6

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