Question

Question 3
If the point $(3,4)$ lies on the graph of the equation $3y=ax+7$, find the value of a.

Answer 1

The point $(3,4)$ lies on the graph of the equation.
$\therefore$ Putting $x=3$ and $y=4$ in the equation $3y=ax+7$, we get
$3\times 4=a\times 3+7$
$\Rightarrow 12=3a+7$
$\Rightarrow 3a=12-7$
$\Rightarrow a=\frac{5}{3}$