Question 3 (ii)
Express 0.4¯7 in the form pq, where p and q are integers and q≠0.
0.4¯7= 0.4777...
=410+0.77710
Let x = 0.777…
⇒ 10x = 7.777… [Since only one digit is repeating, multiply x with 10.]
⇒ 10x = 7+ 0.777...
⇒ 10x = 7 + x
⇒ x=79
Therefore,
0.4¯7=410+x10=410+790=36+790=4390