Question

Question 3(iii)
Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube:
135

Answer 1

135
Prime factors of $135=3\times 3\times 3\times 5$
Here one factor 5 does not appear in a triplet.
Therefore, 135 must be divided by 5 to make it a perfect cube.
$\begin{array}{cc}3& 135\\ 3& 45\\ 3& 15\\ 5& 5\\ & 1\end{array}$