Question 3(iii) Find the value of:
(12)−2+(13)−2+(14)−2
(12)−2+(13)−2+(14)−2=(2−1)−2+(3−1)−2+(4−1)−2 [∵a−m=1am]=2(2)+3(2)+4(2) [∵(am)n=am×n]=22+32+42=4+9+16=29
Question 3(ii) Find the value of:
(2−1×4−1)÷2−2