Question 3 In the following figure, if LM || CB and LN || CD, prove that AMAB=ANAD.
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Solution
In the given figure, LM || CB
By using basic proportionality theorem, we get, MBAM=LCAL MBAM+1=LCAL+1 ABAM=ACAL...(i)
Similarly, LN || CD ∴NDAN=LCAL NDAN+1=LCAL+1 ADAN=ACAL ... (ii)
From (i) and (ii), we get ABAM=ADAN or AMAB=ANAD