Question 3
In the given figure, if AB||DE,∠BAC=35∘and∠CDE=53∘,find∠DCE.
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Solution
AB||DE and AE is a transversal. ∠BAC=∠CED (Alternate interior angles) ∴∠CED=35∘
In ΔCDE, ∠CDE+∠CED+∠DCE=180∘ ( Angle sum property of a triangle) 53∘+35∘+∠DCE=180∘ ∠DCE=180∘−88∘ ∠DCE=92∘