Question 3(iv)
Find the value of:

$(3^{- 1} + 4^{- 1} + 5^{- 1})^{0}$

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Solution

$(3^{- 1} + 4^{- 1} + 5^{- 1})^{0} = {(\frac{1}{3} + \frac{1}{4} + \frac{1}{5})}^{0} [∵ a^{- m} = \frac{1}{a^{m}}] {(\frac{20 + 15 + 12}{60})}^{0} = {(\frac{47}{60})}^{0} = 1 [∵ a^{0} = 1]$

Alternative:

$(3^{- 1} + 4^{- 1} + 5^{- 1})^{0}$
= 1 $[∵ a^{0} = 1]$ (Anything to the power zero is equal to 1.)

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Question 3(iv)
Find the value of:

$\left(3^{-1}+4^{-1}+5^{-1}\right)^0$

{(\frac{2}{3} m + \frac{3}{2} n)}^{2}

\frac{4}{(216)^{- \frac{2}{3}}} + \frac{1}{(256)^{- \frac{3}{4}}} + \frac{2}{(243)^{- \frac{1}{5}}}

x \times x^{2} \times x^{3} \times x^{4}

\frac{4}{(216)^{- \frac{2}{3}}} + \frac{1}{(256)^{- \frac{3}{4}}} + \frac{2}{(243)^{- \frac{1}{5}}}

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