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Question

Question 3 (iv)
In the following APs, find the missing term in the boxes.

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Solution

For this A.P.,a=4a6=6We know that, an=a+(n1)da6=a+(61)d6=4+5d10=5dd=2a2=a+d=4+2=2a3=a+2d=4+2(2)=0a4=a+3d=4+3(2)=2a5=a+4d=4+4(2)=4
Therefore, the missing terms are −2, 0, 2, and 4 respectively.

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