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Question 3
The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also, find the mean monthly expenditure.

Expenditure (in Rs)Number of families1000150024150020004020002500332500300028300035003035004000224000450016450050007


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Solution

From the given data, maximum class frequency is 40 belonging to 1500 - 2000 interval.

So, modal class = 1500 - 2000

Lower limit l of modal class = 1500

Frequency (f1) of modal class = 40

Frequency (f0) of class preceding modal class = 24

Frequency (f2) of class succeeding modal class = 33

Class size h = 500

Mode=l+(f1f02f1f0f2)×h=1500+(40242(40)2433)×500=1500+(168057)×500=1500+800023

= 1500 + 347.826

= 1847.826 = 1847.83

So, modal monthly expenditure was Rs.1847.83

Now, to calculate mean :
we may find class mark as;

Class mark=upper class limit+lower class limit2

Class size h of given data = 500

Now, taking 2750 as assumed mean a we may calculate di,ui and fiui as following:

Expenditure (in Rs)Number of families fixidi=xi2750ui=xi2750hfiui10001500241250150037215002000401750100028020002500332250500133250030002827500003000350030325050013035004000223750100024440004500164250150034845005000747502000428Total200 35

Now, from the table it may be observed that:

fi=200fiui=35¯x(mean)=a+(fiuifi)×h¯x=2750+(35200)×500

= 2750 - 87.5

= 2662.5

So, the mean monthly expenditure was Rs.2662.50.


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