Question

Question 3(v)
Find the value of:

${\left\{{\left(\frac{-2}{3}\right)}^{-2}\right\}}^2$

Answer 1

${\left\{{\left(\frac{-2}{3}\right)}^{-2}\right\}}^2={\left(\frac{-2}{3}\right)}^{-2\times 2}[\because (a^m{)}^n=a^{m\times n}]={\left(\frac{-2}{3}\right)}^{-4}={\left[\frac{3}{-2}\right]}^4[\because a^{-m}=\frac{1}{a^m}]=\frac{81}{16}$