Question 3(v)
Work out the following divisions
$96 a b c (3 a - 12) (5 b - 30) \div 144 (a - 4) (b - 6)$

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Solution

$96 a b c (3 a - 12) (5 b - 30) \div 144 (a - 4) (b - 6) \frac{96 a b c (3 \times a - 3 \times 4) (5 \times b - 2 \times 3 \times 5)}{144 (a - 4) (b - 6)} = \frac{2 a b c \times 3 (a - 4) \times 5 (b - 6)}{3 (a - 4) (b - 6)} = 10 a b c$

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96 a b c (3 a - 12) (5 b - 30) \div 144 (a - 4) (b - 6)

96 a b c (3 a - 12) (5 b + 30) \div 144 (a - 4) (b + 6)

96 a b c (3 a - 12) (5 b - 30) \div 144 (a - 4) (b - 6)

96abc(3a − 12)(5b − 30) ÷ 144(a − 4) (b − 6) gives

96 a b c (3 a - 12) (5 b - 30) \div 144 (a - 4) (b - 6)

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