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Factorisation by Regrouping Terms

Question 3vii...

Question

Question 3(viii)
Factorise the expressions
$10 a b + 4 a + 5 b + 2$

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Solution

$10 a b + 4 a + 5 b + 2 = 10 a b + 5 b + 4 a + 2 = 5 b (2 a + 1) + 2 (2 a + 1) = (2 a + 1) (5 b + 2)$

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Similar questions

Q. Question 3(viii)
Factorise the expressions

10 a b + 4 a + 5 b + 2

Question 28
Expand the following
(i) $(4 a - b + 2 c)^{2}$

(ii) $(3 a - 5 b - c)^{2}$

(iii) $(- x + 2 y - 3 z)^{2}$

Q. Question 4(i)
Subtract 4a - 7 ab + 3b +12 from 12 a - 9 ab + 5b - 3

\frac{a}{b} = \frac{8}{3}

\frac{4 a + 5 b}{4 a - 5 b}

Question 28
Expand the following
(i) $(4 a - b + 2 c)^{2}$

(ii) $(3 a - 5 b - c)^{2}$

(iii) $(- x + 2 y - 3 z)^{2}$

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Factorisation by Regrouping Terms

Standard VIII Mathematics

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