True.
If the given points (-1, 1) and (-3, 3) lies on the linear equation x + y = 0, then both points will satisfy the equation.
So, at point (-1,1) we put x = -1, and y = 1 in LHS of the given equation, we get;
LHS = x + y = - 1 + 1 = 0 = RHS
Again, at point (-3 , 3) put x = - 3 and y = 3 in LHS of the given equation, we get;
LHS = x + y = -3 + 3 = 0 = RHS
Hence, (-1, 1) and (-3, 3) both satisfy the given linear equation x + y = 0.