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Standard X

Mathematics

Arithmetic Progression

Question 3 xI...

Question

Question 3 (x)
In an AP:
(x) Given l = 28, S = 144 and there are total 9 terms. Find a.

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Solution

(x) Given that, l = 28, S = 144 and there are total of 9 terms.
$S_{n} = \frac{n}{2} (a + l) 144 = \frac{9}{2} (a + 28) (16) \times (2) = a + 28 32 = a + 28 a = 4$

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Arithmetic Progression

Standard X Mathematics

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Question 3 (x) In an AP: (x) Given l = 28, S = 144 and there are total 9 terms. Find a.

(x) Given that, l = 28, S = 144 and there are total of 9 terms. Sn=n2(a+l)144=92(a+28)(16)×(2)=a+2832=a+28a=4

Question 3 (x)
In an AP:
(x) Given l = 28, S = 144 and there are total 9 terms. Find a.

(x) Given that, l = 28, S = 144 and there are total of 9 terms.
$S_{n} = \frac{n}{2} (a + l) 144 = \frac{9}{2} (a + 28) (16) \times (2) = a + 28 32 = a + 28 a = 4$