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Standard VII

Mathematics

Solving Equations with Variable on Both Sides

Question 31Fi...

Question

Question 31

Fill in the blanks to make each statement true:

The denominator of a rational number is greater than the numerator by 10. If the numerator is increased by 1 and the denominator is decreased by 1, then expression for new denominator is ..............

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Solution

x+9
Let numerator be x. Then, denominator=x+10
$∴ R a t i o n a l n u m b e r = \frac{x}{x + 10}$
According to the equation,
New rational number= $\frac{N u m e r a t o r + 1}{D e n o m i n a t o r - 1} = \frac{x + 1}{x + 10 - 1} = \frac{x + 1}{x + 9}$
Hence, the new denominator is x+9.

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Solving Equations with Variable on Both Sides

Standard VII Mathematics

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Question 31 Fill in the blanks to make each statement true: The denominator of a rational number is greater than the numerator by 10. If the numerator is increased by 1 and the denominator is decreased by 1, then expression for new denominator is ..............

x+9 Let numerator be x. Then, denominator=x+10 ∴Rational number=xx+10 According to the equation, New rational number= Numerator+1Denominator−1=x+1x+10−1=x+1x+9 Hence, the new denominator is x+9.

Question 31

Fill in the blanks to make each statement true:

The denominator of a rational number is greater than the numerator by 10. If the numerator is increased by 1 and the denominator is decreased by 1, then expression for new denominator is ..............

x+9
Let numerator be x. Then, denominator=x+10
$∴ R a t i o n a l n u m b e r = \frac{x}{x + 10}$
According to the equation,
New rational number= $\frac{N u m e r a t o r + 1}{D e n o m i n a t o r - 1} = \frac{x + 1}{x + 10 - 1} = \frac{x + 1}{x + 9}$
Hence, the new denominator is x+9.