Question

Question 32

In the following question, out of the four options, only one is correct. Write the correct answer.

Cube of $-\frac{1}{2}$ is

(a) $\frac{1}{8}$

(b) $\frac{1}{16}$

(c) $-\frac{1}{8}$

(d) $-\frac{1}{16}$

Answer 1

Cube of a is $(a{)}^3=a\times a\times a$
Similarly ${(-\frac{1}{2})}^3=\left(\frac{-1}{2}\right)\times \left(\frac{-1}{2}\right)\times \left(\frac{-1}{2}\right)=(-\frac{1}{8})$