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Question

Question 33

The value of (a+b)2(ab)2 is
a) 4ab
b) 4ab
c) 2a2+2b2
d) 2a22b2

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Solution

We have,
(a+b)2(ab)2=a2+b2+2ab(a2+b22ab)[ (a+b)2=a2+b2+2ab and (ab)2=a2+b22ab]=a2+b2+2aba2b2+2ab=a2+b2b2a2+2ab+2ab=4ab
[combining the like terms]

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