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Byju's Answer
Standard IX
Mathematics
Factorisation of Quadratic Polynomials- Middle Term Splitting
Question 34Fa...
Question
Question 34
Factorise:
(i)
1
+
64
x
3
(ii)
a
3
−
2
√
2
b
3
Open in App
Solution
(i)
1
+
64
x
3
=
(
1
)
3
+
(
4
x
)
3
=
(
1
+
4
x
)
[
(
1
)
2
–
(
1
)
(
4
x
)
+
(
4
x
)
2
]
[
U
s
i
n
g
t
h
e
i
d
e
n
t
i
t
y
,
a
3
–
b
3
=
(
a
+
b
)
(
a
2
−
a
b
+
b
2
)
]
=
(
1
+
4
x
)
(
1
–
4
x
+
16
x
2
)
(ii)
a
3
−
2
√
2
b
3
=
(
a
)
3
–
(
√
2
b
)
3
=
(
a
−
√
2
b
)
[
a
2
+
a
(
√
2
b
)
+
(
√
2
b
)
2
]
[
U
s
i
n
g
t
h
e
i
d
e
n
t
i
t
y
,
a
3
–
b
3
=
(
a
–
b
)
(
a
2
+
a
b
+
b
2
)
]
(
a
−
√
2
b
)
(
a
2
+
√
2
a
b
+
2
b
2
)
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16
Similar questions
Q.
Question 34
Factorise:
(i)
1
+
64
x
3
(ii)
a
3
−
2
√
2
b
3
Q.
Factorise:
a
3
−
2
√
2
b
3
Q.
Factorise:
a
3
+
3
a
2
b
+
3
a
b
2
+
2
b
3
Q.
Find which is the greater
3
a
b
2
or
a
3
+
2
b
3
.
Q.
State whether the statement is True or False.
Expand:
(
a
−
2
b
)
3
is equal to
a
3
−
6
a
2
b
+
12
a
b
2
−
8
b
3
.
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Factorisation of Quadratic Polynomials- Middle Term Splitting
Standard IX Mathematics
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