CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 34
Kanika was given her pocket money on Jan 1st, 2008. She puts Rs.1 on day 1, Rs.2 on day 2, Rs.3 on day 3 and continued doing so till the end of the month, from this money into her piggy bank she also spent Rs.204 of her pocket money and found that at the end of the month she still had Rs.100 with her. How much was her pocket money for the month?

Open in App
Solution

Let her pocket money be Rs. x.
From this money, she takes Rs.1 on day 1, Rs. 2 on day 2, Rs.3 on day 3 and so on until the end of the month.
1 + 2 + 3 + 4 + ….. + 31
Which form an AP in which, number of terms is 31, first term (a) = 1 and common difference (d) = 2 – 1 = 1
Sum of n terms Sn=n2[2a+(n1)d]
S31=312[2×1+(311)×1]
=312(2+30)=31×322
=31×16=496
So, Kanika takes Rs. 496 till the end of the month from x.
Also, she spent Rs. 204 of her pocket money and found that at the end of the month she still has Rs. 100 with her.
Now, according the condition,
(x - 496) - 204 = 100
x - 700 = 100
x = Rs. 800
Hence, Rs. 800 was her pocket money for the month.

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon