Question

Question 36
Length of one of the diagonals of a rectangle whose sides are 10 cm and 24 cm is
a) 25 cm
b) 20 cm
c) 26 cm
d) 3.5 cm

Answer 1

In $\Delta BCD$,
$\angle BDC={90}^{\circ }$
$\therefore$ Using Pythagoras theorem,
$B{C}^2=B{D}^2+C{D}^2$
$\Rightarrow B{C}^2={10}^2+{24}^2=100+576\Rightarrow B{C}^2=676\Rightarrow BC=\sqrt{676}\Rightarrow BC=26cm$